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The solution of problem (15) is.<i>c<\/i>\u2009=\u2009(8.581, 6.1466, 9.96877), <i>\u03b8<\/i>\u2009=\u20091.6, <i>\u03c8<\/i>\u2009=\u20090.58112.<i>X<\/i><sub><i>1<\/i><\/sub> = \u2212516.22, <i>X<\/i><sub>2<\/sub>\u2009=\u2009\u2013451.7, <i>X<\/i><sub>3<\/sub>\u2009=\u2009\u2013371.435,<i>a<\/i><sub>1<\/sub>(<i>X<\/i><sub>1<\/sub>)\u2009=\u20090.804\u2009<\u2009<i>\u03b3<\/i><sub>1<\/sub>\u2009=\u20090.95. <i>a<\/i><sub>2<\/sub>(<i>X<\/i><sub>2<\/sub>)\u2009=\u20090.595\u2009<\u2009<i>\u03b3<\/i><sub>2<\/sub>\u2009=\u20090.85.<i>a<\/i><sub>3<\/sub>(<i>X<\/i><sub>3<\/sub>)\u2009=\u20090.581\u2009<\u2009<i>\u03c3<\/i><sub>1<\/sub>\u2009=\u20090.7412. <i>\u03c3<\/i><sub>2<\/sub>\u2009=\u20090.9755.Both of DM<sub>1<\/sub> and DM<sub>2<\/sub> aren\u2019t satisfied with the above solution, so if DM<sub>2<\/sub> changes <i>\u03b3<\/i><sub><i>2<\/i><\/sub>\u2009=\u20090.85 to <i>\u03b3<\/i><sup><i>'<\/i><\/sup><sub>2<\/sub>\u2009=\u20090.65. So the corresponding problem of (16) is formulated as:The solution of problem (19) is <i>c<\/i>\u2009=\u2009(8.791, 7.257, 8.916), <i>\u03b8<\/i>\u2009=\u20092.1, <i>\u03c8<\/i>\u2009=\u20090.558775,<i>X<\/i><sub><i>1<\/i><\/sub>= \u2212519.09, <i>X<\/i><sub><i>2<\/i><\/sub>= \u2212453.12, <i>X<\/i><sub><i>3<\/i><\/sub>\u2009=\u2009\u2212371.4, a<sub>1<\/sub>(<i>X<\/i><sub><i>1<\/i><\/sub>)\u2009=\u20090.865072\u2009<\u2009<i>\u03b3<\/i><sub><i>1<\/i><\/sub>=\u20090.95,<i>a<\/i><sub><i>2<\/i><\/sub>(<i>X<\/i><sub><i>2<\/i><\/sub>)\u2009=\u20090.65, <i>a<\/i><sub><i>3<\/i><\/sub>(<i>X<\/i><sub><i>3<\/i><\/sub>)\u2009=\u20090.558775, <i>\u03c3<\/i><sub>1<\/sub>\u2009=\u20090.7514, <i>\u03c3<\/i><sub>2<\/sub>\u2009=\u20090.8596.The termination condition (7) isn't satisfied the value of <i>a<\/i><sub>1<\/sub>(<i>X<\/i><sub>1<\/sub>), if DM<sub>1<\/sub> changes \u03b3<sub>2<\/sub>\u2009=\u20090.95 to <i>\u03b3<\/i><sup><i>'<\/i><\/sup><sub>1<\/sub>\u2009=\u20090.91 then solves the problem (20);The solution of problem (14) is.<i>c<\/i>\u2009=\u2009(8.873, 9.246, 7.917), <i>\u03b8<\/i>\u2009=\u20091.513, <i>\u03c8<\/i>\u2009=\u20090.537895.<i>X<\/i><sub><i>1<\/i><\/sub> = \u2212518.12, <i>X<\/i><sub>2<\/sub>\u2009=\u2009\u2212450.36, <i>X<\/i><sub>3<\/sub>\u2009=\u2009\u2212369.57,<i>a<\/i><sub><i>1<\/i><\/sub>(<i>X<\/i><sub>1<\/sub>)\u2009=\u20090.91, <i>a<\/i><sub><i>2<\/i><\/sub>(<i>X<\/i><sub>2<\/sub>)\u2009=\u20090.701, <i>a<\/i><sub><i>3<\/i><\/sub>(<i>X<\/i><sub>3<\/sub>)\u2009=\u20090.5379,<i>\u03c3<\/i><sub>1<\/sub>\u2009=\u20090.778453, <i>\u03c3<\/i><sub>2<\/sub>\u2009=\u20090.767755.By now, <i>a<\/i><sub><i>1<\/i><\/sub>(<i>X<\/i><sub>1<\/sub>)\u2009=\u20090.91\u2009=\u2009<i>\u03b3<\/i><sup><i>'<\/i><\/sup><sub>1<\/sub>, <i>a<\/i><sub><i>2<\/i><\/sub>(<i>X<\/i><sub>2<\/sub>)\u2009=\u20090.701\u2009>\u20090.65\u2009=\u2009<i>\u03b3<\/i><sup><i>'<\/i><\/sup><sub>2<\/sub>,Moreover <i>\u03c3<\/i><sub>1<\/sub>\u2009=\u20090.778453, <i>\u03c3<\/i><sub>2<\/sub>\u2009=\u20090.767755 are all in [0.75, 0.9]. This is meaning that, all the proposed algorithm's termination conditions are satisfied, the DMs find the adequate solution.","order":5,"name":"Ethics","group":{"name":"EthicsHeading","label":"Appendix"}}]}}